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4p^2-2=7p
We move all terms to the left:
4p^2-2-(7p)=0
a = 4; b = -7; c = -2;
Δ = b2-4ac
Δ = -72-4·4·(-2)
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{81}=9$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-9}{2*4}=\frac{-2}{8} =-1/4 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+9}{2*4}=\frac{16}{8} =2 $
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